In the following compounds,the order of basic | vedclass

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Question

(A) The basicity of amines depends on the availability of the lone pair of electrons on the nitrogen atom.$I$ (Piperidine): The nitrogen atom is $sp^3

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$I > III > II > IV$

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(A) The basicity of amines depends on the availability of the lone pair of electrons on the nitrogen atom.$I$ (Piperidine): The nitrogen atom is $sp^3$ hybridized,and the lone pair is not involved in resonance. It is the most basic.$II$ (Pyridine): The nitrogen atom is $sp^2$ hybridized. The lone pair is in an $sp^2$ orbital,which is more electronegative than an $sp^3$ orbital,making it less basic than piperidine.$III$ (Morpholine): Similar to piperidine,the nitrogen is $sp^3$ hybridized,but the presence of an electronegative oxygen atom exerts an inductive effect ($-I$ effect),which reduces the electron density on the nitrogen atom,making it less basic than piperidine but more basic than pyridine.$IV$ (Pyrrole): The nitrogen atom is $sp^2$ hybridized,and its lone pair is involved in the aromatic sextet (delocalized). Thus,it is the least basic.Therefore,the order of basicity is $I > III > II > IV$.

In the following compounds,the order of basicity is as follows:

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